-112=-16x^2+96x

Solution for -112=-16x^2+96x equation:

-112=-16x^2+96x

We move all terms to the left:

-112-(-16x^2+96x)=0

We get rid of parentheses

16x^2-96x-112=0

a = 16; b = -96; c = -112;
Δ = b2-4ac
Δ = -962-4·16·(-112)
Δ = 16384
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{16384}=128$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-96)-128}{2*16}=\frac{-32}{32}
=-1
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-96)+128}{2*16}=\frac{224}{32}
=7
$